u+1^2=2u^2-5u+13

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Solution for u+1^2=2u^2-5u+13 equation: 



u+1^2=2u^2-5u+13

We move all terms to the left:

u+1^2-(2u^2-5u+13)=0

We add all the numbers together, and all the variables

u-(2u^2-5u+13)+1=0

We get rid of parentheses

-2u^2+u+5u-13+1=0

We add all the numbers together, and all the variables

-2u^2+6u-12=0

a = -2; b = 6; c = -12;
Δ = b2-4ac
Δ = 62-4·(-2)·(-12)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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